合成路线1

This compound can be prepared in several ways from the lactone (I), which is obtained by treatment of benzyl cyanide (A) and epichlorhydrin (B) with sodium amide: 1) The opening of lactone (I) with SOBr2-ethanol gives a bromo ester, which is treated successively by ammonia and sodium hydroxide to yield the amino acid (II). The reaction of (II) with SOCl2 and diethylamine in ethanol gives the final product, which is converted to the hydrochloric salt by treatment with HCl ethanol. 2) Lactone (I), opened with 33% HBr-AcOH, gives the bromo acid (III), which is treated by SOCl2 and then diethylamine in ethanol. The bromoamide (IV) reacts with potassium phthalimide and is deprotected by hydrazine or methylamine to yield, after salification, title compound. 3) Lactone (I) is treated by potassium phthalimide and then SOCl2 and diethylamine in EtOH to give compound (V), treated as above. 4) Bromoamide (IV) can be treated by hexamethylenetetramine in butanol and hydrolyzed by refluxing with 15% HCl in ethanol.